Alg1.1.14

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$\left((0.5^{-2})\right)^2\,$

Since $0.5=\frac{1}{2}=2^{-1}\,$ , we can write

$=\left(\left((2^{-1})^{-2}\right)\right)^2\,$

Use the exponent rule $(a^n)^m=a^{nm}\,$ to get

$=2^{(-1)(-2)2}\,$

$=2^4\,$

$=16\,$

Main Page : Algebra : Algebra-Exponents

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